2037. Minimum Number of Moves to Seat Everyone

Easy

There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the i^th seat. You are also given the array students of length n, where students[j] is the position of the j^th student.

You may perform the following move any number of times:

Increase or decrease the position of the i^th student by 1 (i.e., moving the i^th student from position x to x + 1 or x - 1)

Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat.

Note that there may be multiple seats or students in the same position at the beginning.

Example 1:

Input: seats = [3,1,5], students = [2,7,4]
Output: 4
Explanation: The students are moved as follows:
- The first student is moved from from position 2 to position 1 using 1 move.
- The second student is moved from from position 7 to position 5 using 2 moves.
- The third student is moved from from position 4 to position 3 using 1 move.
In total, 1 + 2 + 1 = 4 moves were used.

Example 2:

Input: seats = [4,1,5,9], students = [1,3,2,6]
Output: 7
Explanation: The students are moved as follows:
- The first student is not moved.
- The second student is moved from from position 3 to position 4 using 1 move.
- The third student is moved from from position 2 to position 5 using 3 moves.
- The fourth student is moved from from position 6 to position 9 using 3 moves.
In total, 0 + 1 + 3 + 3 = 7 moves were used.

Example 3:

Input: seats = [2,2,6,6], students = [1,3,2,6]
Output: [0,1]
Explanation: Note that there are two seats at position 2 and two seats at position 6.

The students are moved as follows:

The first student is moved from from position 1 to position 2 using 1 move.
The second student is moved from from position 3 to position 6 using 3 moves.
The third student is not moved.
The fourth student is not moved.

In total, 1 + 3 + 0 + 0 = 4 moves were used.

Constraints:

n == seats.length == students.length
1 <= n <= 100
1 <= seats[i], students[j] <= 100

Solution:

class Solution {

    /**
     * @param Integer[] $seats
     * @param Integer[] $students
     * @return Integer
     */
    function minMovesToSeat($seats, $students) {
        $ans = 0;

        sort($seats);
        sort($students);

        for ($i = 0; $i < count($seats); $i++) {
            $ans += abs($seats[$i] - $students[$i]);
        }

        return $ans;
    }
}

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