What is leaf node?
The node have no children .
We have to count how many leaf nodes in a tree .
We will do it by recursion . If the root is NULL that means there is no tree . So we will return 0 . If a node's left node is NULL && right node is also NULL that means it is a leaf node .
We will return l+r . We are not calculating all nodes. That's why we are not returning l+r+1 . We are only returning child node .
Let's take a new tree .
#include <bits/stdc++.h>
using namespace std;
class Node
{
public:
int val;
Node *right;
Node *left;
Node(int value)
{
this->val = value;
this->right = NULL;
this->left = NULL;
}
};
Node *input_tree()
{
int val;
cin >> val;
Node *root;
if (val == -1)
root = NULL;
else
root = new Node(val);
queue<Node *> q;
if (root)
q.push(root);
while (!q.empty())
{
Node *p = q.front();
q.pop();
Node *myLeft;
Node *myRight;
int l, r;
cin >> l >> r;
if (l == -1)
myLeft = NULL;
else
myLeft = new Node(l);
if (r == -1)
myRight = NULL;
else
myRight = new Node(r);
p->left = myLeft;
p->right = myRight;
if (p->left)
q.push(p->left);
if (p->right)
q.push(p->right);
}
return root;
}
void level_order(Node *root)
{
if (root == NULL)
{
cout << "Tree nai " << endl;
return;
}
queue<Node *> q;
q.push(root);
while (!q.empty())
{
Node *f = q.front();
q.pop();
cout << f->val << " ";
if (f->left)
q.push(f->left);
if (f->right)
q.push(f->right);
}
}
int count_leaf_node(Node *root)
{
if (root == NULL)
return 0 ;
if (root->left == NULL && root->right == NULL)
return 1;
int l = count_leaf_node(root->left) ;
int r = count_leaf_node(root->right) ;
return l + r;
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
Node *root = input_tree();
cout << count_leaf_node(root) ;
}