Multidimensional array--matrix

Neelakandan R - Feb 28 - - Dev Community

Gross matrix:X

package afterfeb13;

public class multidimarray {
    public static void main(String[] args) {
        int[][] mark = { { 10, 20, 80 }, { 40, 50, 60 }, { 70, 80, 90 } };
        int total = 0;
        int sum = 0;
        for (int row = 0; row < mark.length; row++) {
            for (int col = 0; col < mark[row].length; col++) {
                if (row + col == 2) {
                    total = total + mark[row][col];
                }
                if (col == row) {
                    sum = sum + mark[row][col];

                }
            }

        }System.out.println("row + col == 2 = " + total);
        System.out.println("col==row = " + sum);
        System.out.println("sum+total = "+ (sum+total));
    }

}

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Output:

row + col == 2 = 200
col==row = 150
sum+total = 350

maxium 1 present in which index:

public class multidimentional {
    public static void main(String[] args) {
        int[][] arr = { { 1, 1, 1, 1, 0 }, { 1, 1, 1, 0, 0 }, { 0, 1, 0, 1, 0 } };
        int max = 0;
        int row_MaxOne = 0;
        for (int row = 0; row < arr.length; row++) {
            int count = 0;
            for (int col = 0; col < arr[row].length; col++) {
                if (arr[row][col] == 1) {

                    count++;

                }
            }

            // System.out.println(row + "index count = " + count + " ");
            if (count > max) {
                max = count;
                row_MaxOne = row;// sending row index[0][1][2]
            }
        }
        System.out.println("index has max ones = " + row_MaxOne + "th index");
        System.out.println("max one present is = " + max);

    }

}


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Output:

index has max ones = 0th index
max one present is = 4

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