recursion sum of array

saurabh belote - Oct 16 '21 - - Dev Community
arr = [90,2,3,4,5,6,7,8,9,101]
n = len(arr)
i = 0
Num = 0
def recursor(n,i,Num):
    if n == 0:
        return n
    else:
        #print(arr[i])
        Num = arr[i] + Num
        print(Num)
        i += 1
        return recursor(n-1,i,Num)

(recursor(n,i,Num))

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