JavaScript Implementation of FizzBuzz in functional programming

0xkoji - Jul 27 '21 - - Dev Community

The FizzBuzz problem is a classic test given in coding interviews. The task is simple: Print integers 1 to N, but print “Fizz” if an integer is divisible by 3, “Buzz” if an integer is divisible by 5, and “FizzBuzz” if an integer is divisible by both 3 and 5.

const isFizz = number => number%3 ==0;
const isBuzz = number => number%5 ==0;

const range = (start, end) => [...new Array(end - start).keys()].map((n) => n + start);

const doFizzBuzz = (start, end) => range(start, end).map((number => {
  if(isFizz(number) && isBuzz(number)) {
    return 'FizzBuzz';
  } else if(isFizz(number)) {
    return 'Fizz';
  } else if(isBuzz(number)) {
    return 'Buzz';
  } else {
    return number;
  }
 }))
 .join(`\n`);

console.log(doFizzBuzz(1, 101));
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jsfiddle

https://jsfiddle.net/381g4fct/7/

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